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(14,27)同開__下(2,3,4)期:(2中1)
(14,27)_(113124期),下4期=39
(14,27)_(113196期),下4期=30,39
(14,27)_(113215期),下3期=39
(14,27)_(114027期),下3期=39
(14,27)_(114064期),下4期=30
(14,27)_(114164期),下4期=39
(14,27)_(114175期),下2期=39,下3期=39
(14,27)_(114268期),下2期=30,下4期=30
(14,27)_(115092期),下2期=30
(14,27)_(115202期),下2期=30,下4期=30
(14,27)_(115257期),下(2,3,4期)
115261期=,??